Given a permutation arrays A[] consisting of N numbers in range [1, N], the task is to left rotate all the even numbers and right rotate all the odd numbers of the permutation and print the updated permutation. 
Note: N is always even.

Examples: 

Input: A = {1, 2, 3, 4, 5, 6, 7, 8} 
Output: {7, 4, 1, 6, 3, 8, 5, 2} 
Explanation: 
Even element = {2, 4, 6, 8} 
Odd element = {1, 3, 5, 7} 
Left rotate of even number = {4, 6, 8, 2} 
Right rotate of odd number = {7, 1, 3, 5} 
Combining Both odd and even number alternatively.
Input: A = {1, 2, 3, 4, 5, 6} 
Output: {5, 4, 1, 6, 3, 2} 

Approach:

1. It is clear that the odd elements are always on even index and even elements are always laying on odd index.
2. To do left rotation of even number we choose only odd indices.
3. To do right rotation of odd number we choose only even indices.
4. Print the updated array.

Below is the implementation of the above approach:

# Python3 program for the above approach

# Function to left rotate
def left_rotate(arr):
	
	last = arr[1];
	for i in range(3, len(arr), 2):
		arr[i - 2] = arr[i]
		
	arr[len(arr) - 1] = last

# Function to right rotate
def right_rotate(arr):
	
	start = arr[len(arr) - 2]
	for i in range(len(arr) - 4, -1, -2):
		arr[i + 2] = arr[i]
		
	arr[0] = start

# Function to rotate the array
def rotate(arr):
	
	left_rotate(arr)
	right_rotate(arr)
	for i in range(len(arr)):
		print(arr[i], end = " ")

# Driver code
arr = [ 1, 2, 3, 4, 5, 6 ]

rotate(arr);

# This code is contributed by sanjoy_62

Output:

5 4 1 6 3 2