Write a program that accepts a number from the user and prints “Even” if the entered number is even and prints “Odd” if the number is odd. You are not allowed to use any comparison (==, <,>,…etc) or conditional statements (if, else, switch, ternary operator,. Etc).

Method 1 
Below is a tricky code can be used to print “Even” or “Odd” accordingly. 

#include 

using namespace std;

int main()
{
	char arr[2][5] = { "Even", "Odd" };
	int no;
	cout << "Enter a number: ";
	cin >> no;
	cout << arr[no % 2];
	getchar();
	return 0;
}

Method 2 
Below is another tricky code can be used to print “Even” or “Odd” accordingly. Thanks to student for suggesting this method.

#include
int main()
{
	int no;
	printf("Enter a no: ");
	scanf("%d", &no);
	(no & 1 && printf("odd"))|| printf("even");
	return 0;
}

Output

Enter a no: even

Please write comments if you find the above code incorrect, or find better ways to solve the same problem

Method 3
This can also be done using a concept known as Branchless Programming. Essentially, make use of the fact that a true statement in Python (other some other languages) evaluates to 1 and a false statements evaluates to false.

# code
n = int(input("Enter a number: "))
print("Even" * (n % 2 == 0), "Odd" * (n % 2 != 0))

Output

Enter a number: Even