How to compare of double and float primitive types in Java

Consider the following two codes in Java:

 
// This program prints true
class Geeksforgeeks {
public static void main(String args[]) {
	float f = 5.25f;
	double d = 5.25
	System.out.println(f == d);
}
}

Output

true

 

// But this program prints false.
class Geeksforgeeks {
public static void main(String args[]) {
	float f = 5.1f;
	double d = 5.1;
	System.out.println(f == d);
}
}

Output

false

The output is true within the first example and false in second. we all know that precisions of float and double are different. Size of mantissa for float is 24 and 53 for double.

Let us consider the primary example of 5.25. Binary representation of integral part is 101 and binary representation of a part of the dot is 0.01 (needs only two bits)

Let us consider the second example 5.1. The binary representation of an integral part is that the same. But binary representation of 0.1 is 1/16 + 1/32 + 1/64 + 1/128 ….. then on until we reach the top of mantissa or sum becomes quite 0.1. during this case, we reach the top of mantissa and thus the worth of 5.1 becomes different in float and double.

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