If we take a look at this problem carefully, we can see that the idea of “loop” is to track some counter value e.g. “i=0” till “i <= 100”. So if we aren’t allowed to use loop, how else can be track something in C language!
Well, one possibility is the use of ‘recursion’ provided we use the terminating condition carefully. Here is a solution that prints numbers using recursion.
Method-1:
#include // Prints numbers from 1 to n void printNos(unsigned int n) { if(n > 0) { printNos(n - 1); printf("%d ", n); } return; } // Driver code int main() { printNos(100); getchar(); return 0; }
Output :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100
Method 2:
C++
// C++ program #include <bits/stdc++.h> using namespace std; void printNos(int initial, int last) { if (initial <= last) { cout << initial << " "; printNos(initial + 1, last); } } int main() { printNos(1, 100); return 0; } // This code is contributed by ukasp.
Output
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100